Actually... I am getting silly. I was going to go Into figuring out a way to precisely figure out the loss but you can measure that with a thermometer and a cooler and evaluating how quickly the pump changes the tempurature of a small body of water, or measuring it's unloaded amp draw at a given voltage.Let me get back to you.
I have some ideas.
But what's probably easier is to assume that since a professional swashplate pump with ideal materials runs in the upper 90% efficiency range, then a hobby built pump is probably in the range of a steel gear pump, around 85% efficient. That gives you the multiplier 1456 which is a fun number to punch into a calculator and easily remembered.
Use that in the hydraulic equation and I'm guessing you should be pretty safe. At least here, wasted energy heating the working fluid is desirable vs a hydraulic system