Entropy455
Well-Known Member
- Joined
- Oct 27, 2011
- Messages
- 303
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I am a new board member, looking to design and build my first engine (hit-and-miss) and I have a few questions.
What compression ratio do you guys typically incorporate within your designs? I understand that back in the day of 60 octane gasoline, engines were made with 5:1 compression. But with modern gasoline, Im thinking 8:1 would be more appropriate?
My next question is on flywheel design. I recently picked up a nice used cast iron flywheel. Its just under 9 in diameter, and weighs about 12 pounds. It was used in a relatively high RPM application (treadmill DC motor flywheel) so its got a very good factory balance.
I want to use this flywheel in my first attempt at building a hit-and-miss engine, and Im trying to determine an appropriate bore and stroke for the engine.
Below are my design requirements:
Desired compression ratio = 8:1
Desired minimum operating speed = 120 RPM
Stroke = 1.5 times the bore
Fuel = gasoline
Ignition = spark
Design process:
The flywheel has a rotating inertia of 1.345 lbm-ft^2.
At 120 RPM, the flywheel kinetic energy is 3.301 ft-lbf
So the question is - what volume of air will the flywheel just be able to pump on the compression stroke?
Air at 70 degrees F has an enthalpy of 126.66 Btu/lbm.
Assuming a polytrophic compression (at 8:1), the compression stroke will increase the airs enthalpy to 288.76 Btu/lbm. The airs temperature will be 730 degrees F, and the pressure will be 263.6 psia.
Thus the energy input required on the compression stroke is 162.1 Btu/lbm, or 126,140 ft-lbf/lbm.
With this specific energy requirement, the flywheels 3.301 ft-lbf of energy would just be able to compress 2.617 x 10^-5 lbm of air.
Air at 70 degrees F, and 14.7 psia, has a density of 4.333 x 10^-5 lbm/in^3, and 2.617 x 10^-5 lbm of air has a volume of 0.6037 in^3.
Thus if stroke = 1.5 times the bore, the engine would have a 0.8 bore, and a 1.2 stroke.
Discussion: obviously this will not work, as the flywheel will come to a virtual stop under the compression stroke. With friction losses, it will likely fall just short of just completing the compression stroke. I neglected the rotating inertia of the crankshaft, because the crankshaft inertia contribution would be relatively small compared to that of the flywheel.
So Ive got a few options for using this flywheel: I can either lower the compression ratio, which would reduce the specific power consumption on the compression stroke. Or reduce engine displacement, or increase the minimum operating engine rpm.
What would you guys do? Recommendations???
What compression ratio do you guys typically incorporate within your designs? I understand that back in the day of 60 octane gasoline, engines were made with 5:1 compression. But with modern gasoline, Im thinking 8:1 would be more appropriate?
My next question is on flywheel design. I recently picked up a nice used cast iron flywheel. Its just under 9 in diameter, and weighs about 12 pounds. It was used in a relatively high RPM application (treadmill DC motor flywheel) so its got a very good factory balance.
I want to use this flywheel in my first attempt at building a hit-and-miss engine, and Im trying to determine an appropriate bore and stroke for the engine.
Below are my design requirements:
Desired compression ratio = 8:1
Desired minimum operating speed = 120 RPM
Stroke = 1.5 times the bore
Fuel = gasoline
Ignition = spark
Design process:
The flywheel has a rotating inertia of 1.345 lbm-ft^2.
At 120 RPM, the flywheel kinetic energy is 3.301 ft-lbf
So the question is - what volume of air will the flywheel just be able to pump on the compression stroke?
Air at 70 degrees F has an enthalpy of 126.66 Btu/lbm.
Assuming a polytrophic compression (at 8:1), the compression stroke will increase the airs enthalpy to 288.76 Btu/lbm. The airs temperature will be 730 degrees F, and the pressure will be 263.6 psia.
Thus the energy input required on the compression stroke is 162.1 Btu/lbm, or 126,140 ft-lbf/lbm.
With this specific energy requirement, the flywheels 3.301 ft-lbf of energy would just be able to compress 2.617 x 10^-5 lbm of air.
Air at 70 degrees F, and 14.7 psia, has a density of 4.333 x 10^-5 lbm/in^3, and 2.617 x 10^-5 lbm of air has a volume of 0.6037 in^3.
Thus if stroke = 1.5 times the bore, the engine would have a 0.8 bore, and a 1.2 stroke.
Discussion: obviously this will not work, as the flywheel will come to a virtual stop under the compression stroke. With friction losses, it will likely fall just short of just completing the compression stroke. I neglected the rotating inertia of the crankshaft, because the crankshaft inertia contribution would be relatively small compared to that of the flywheel.
So Ive got a few options for using this flywheel: I can either lower the compression ratio, which would reduce the specific power consumption on the compression stroke. Or reduce engine displacement, or increase the minimum operating engine rpm.
What would you guys do? Recommendations???